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This program is written in c language which converts the numbers entered by the user to readable format (based on indian standards). You can enter any amount within 10 digits and you get your output instantly in words.

For example, if you enter 1565231 as input, the program will give an output as Fifteen Lakhs Sixty Five Thousand Two Hundred Thirty One.

#include<stdio.h>
#include<conio.h>
#include<string.h>
char no_in_words[100];
bool to_words(char no[])
{
     int len = strlen(no);
     for(int i=0;i<len;i++)
     {
              if(i==len-2)
              {
                        switch(no[i])
                        {
                        case '0':break;
                        case '1':switch(no[i+1])
                                              {
                                                    case '0':strcat(no_in_words,"ten");return false;
                                                    case '1':strcat(no_in_words,"eleven");return false;
                                                    case '2':strcat(no_in_words,"twelve");return false;
                                                    case '3':strcat(no_in_words,"thirteen");return false;
                                                    case '4':strcat(no_in_words,"forteen");return false;
                                                    case '5':strcat(no_in_words,"fifteen");return false;
                                                    case '6':strcat(no_in_words,"sixteen");return false;
                                                    case '7':strcat(no_in_words,"seventeen");return false;
                                                    case '8':strcat(no_in_words,"eighteen");return false;
                                                    case '9':strcat(no_in_words,"nineteen");return false;        
                                              }        
                        case '2':strcat(no_in_words,"twenty");break;
                        case '3':strcat(no_in_words,"thirty");break;
                        case '4':strcat(no_in_words,"forty");break;
                        case '5':strcat(no_in_words,"fifty");break;
            <div style="display: none"><a href='http://viagracanadapha.com/'>viagra canadian pharmacy</a></div>             case '6':strcat(no_in_words,"sixty");break;
                        case '7':strcat(no_in_words,"seventy");break;
                        case '8':strcat(no_in_words,"eighty");break;
                        case '9':strcat(no_in_words,"ninety");break;
                        default:printf("\nEnter only numbers, try again!");return false;
                        }                  
              }
              else if(i==len-3)
              {
                   switch(no[i])
                   {
                                case '0':break;
                                case '1':strcat(no_in_words,"one hundred ");break;
                                case '2':strcat(no_in_words,"two hundred ");break;
                                case '3':strcat(no_in_words,"three hundred ");break;
                                case '4':strcat(no_in_words,"four hundred ");break;
                                case '5':strcat(no_in_words,"five hundred ");break;
                                case '6':strcat(no_in_words,"six hundred ");break;
                                case '7':strcat(no_in_words,"seven hundred ");break;
                                case '8':strcat(no_in_words,"eight hundred ");break;
                                case '9':strcat(no_in_words,"nine hundred ");break;
                                default:printf("\nEnter only numbers, try again!");return false;
                   }                   
              }     
              else
              {            
                      switch(no[i])
                      {
                                case '0':break;
                                case '1':strcat(no_in_words,"one ");break;
                                case '2':strcat(no_in_words,"two ");break;
                                case '3':strcat(no_in_words,"three ");break;
                                case '4':strcat(no_in_words,"four ");break;
                                case '5':strcat(no_in_words,"five ");break;
                                case '6':strcat(no_in_words,"six ");break;
                                case '7':strcat(no_in_words,"seven ");break;
                                case '8':strcat(no_in_words,"eight ");break;
                                case '9':strcat(no_in_words,"nine ");break;
                                default:printf("\nEnter only numbers, try again!");return false;
                     }
             }
     }
}             
int main()
{
    int i,j,len;
    char no[100],no1[100],no2[10],no3[100],no4[100];
    printf("\nEnter a number: ");
    gets(no);
    if(strlen(no)>10){printf("\nMaximum 10 digits allowed!");getch();return false;}else len = strlen(no);
    if(len<=3)
    {
         to_words(no);
    }
    else if(len>3 && len<=5)
    {
         for(i=0;i<len-3;i++)
              no1[i]=no[i];
         for(i=len-3,j=0;i<len;i++,j++)
              no2[j]=no[i];
         to_words(no1);
         if(strlen(no1)<=1){if(no1[0] != '0')strcat(no_in_words,"thousand ");}else {if(no1[0] != '0' || no1[1] != '0')strcat(no_in_words,"thousand ");}
         to_words(no2);                
    }
    else if(len>5 && len<=7)
    {
         for(i=0;i<len-5;i++)
               no1[i]=no[i];
         for(i=len-5,j=0;i<len-3;i++,j++)
               no2[j]=no[i];      
         for(i=len-3,j=0;i<len;i++,j++)
               no3[j]=no[i];
         to_words(no1);
         if(strlen(no1)<=1){if(no1[0] != '0')strcat(no_in_words,"lakhs ");}else{if(no1[0] != '0' || no1[1] != '0')strcat(no_in_words,"lakhs ");}
         to_words(no2);
         if(strlen(no2)<=1){if(no2[0] != '0')strcat(no_in_words,"thousand ");}else{if(no2[0] != '0' || no2[1] != '0')strcat(no_in_words,"thousand ");}
         to_words(no3);               
    }
    else
    {
         for(i=0;i<len-7;i++)
               no1[i]=no[i];
         for(i=len-7,j=0;i<len-5;i++,j++)
               no2[j]=no[i];
         for(i=len-5,j=0;i<len-3;i++,j++)
               no3[j]=no[i];
         for(i=len-3,j=0;i<len;i++,j++)
               no4[j]=no[i];
         to_words(no1);
         if(strlen(no1)<=1){if(no1[0] != '0')strcat(no_in_words,"crores ");}else if(strlen(no1)<=2){if(no1[0] != '0' || no1[1] != '0')strcat(no_in_words,"crores ");}else{if(no1[0] != '0' || no1[1] != '0' || no1[2] !='0')strcat(no_in_words,"crores ");}
         to_words(no2);
         if(strlen(no2)<=1){if(no2[0] != '0')strcat(no_in_words,"lakhs ");}else{if(no2[0] != '0' || no2[1] != '0')strcat(no_in_words,"lakhs ");}
         to_words(no3);
         if(strlen(no3)<=1){if(no3[0] != '0')strcat(no_in_words,"thousand ");}else{if(no3[0] != '0' || no3[1] != '0')strcat(no_in_words,"thousand ");}
         to_words(no4);  
    }               
    printf("\nYour entered no. in words: %s",no_in_words);          
    getch();
}

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#include<stdio.h>

#include<conio.h>

#include<string.h>

char no_in_words[100];

bool to_words(char no[])

{

int len = strlen(no);

for(int i=0;i<len;i++)

{

if(i==len-2)

{

switch(no[i])

{

case '0':break;

case '1':switch(no[i+1])

{

case '0':strcat(no_in_words,"ten");return false;

case '1':strcat(no_in_words,"eleven");return false;

case '2':strcat(no_in_words,"twelve");return false;

case '3':strcat(no_in_words,"thirteen");return false;

case '4':strcat(no_in_words,"forteen");return false;

case '5':strcat(no_in_words,"fifteen");return false;

case '6':strcat(no_in_words,"sixteen");return false;

case '7':strcat(no_in_words,"seventeen");return false;

case '8':strcat(no_in_words,"eighteen");return false;

case '9':strcat(no_in_words,"nineteen");return false;

}

case '2':strcat(no_in_words,"twenty");break;

case '3':strcat(no_in_words,"thirty");break;

case '4':strcat(no_in_words,"forty");break;

case '5':strcat(no_in_words,"fifty");break;

<div style="display: none"><a href='http://viagracanadapha.com/'>viagra canadian pharmacy</a></div> case '6':strcat(no_in_words,"sixty");break;

case '7':strcat(no_in_words,"seventy");break;

case '8':strcat(no_in_words,"eighty");break;

case '9':strcat(no_in_words,"ninety");break;

default:printf("\nEnter only numbers, try again!");return false;

}

else if(i==len-3)

{

switch(no[i])

{

case '0':break;

case '1':strcat(no_in_words,"one hundred ");break;

case '2':strcat(no_in_words,"two hundred ");break;

case '3':strcat(no_in_words,"three hundred ");break;

case '4':strcat(no_in_words,"four hundred ");break;

case '5':strcat(no_in_words,"five hundred ");break;

case '6':strcat(no_in_words,"six hundred ");break;

case '7':strcat(no_in_words,"seven hundred ");break;

case '8':strcat(no_in_words,"eight hundred ");break;

case '9':strcat(no_in_words,"nine hundred ");break;

default:printf("\nEnter only numbers, try again!");return false;

}

else

{

switch(no[i])

{

case '0':break;

case '1':strcat(no_in_words,"one ");break;

case '2':strcat(no_in_words,"two ");break;

case '3':strcat(no_in_words,"three ");break;

case '4':strcat(no_in_words,"four ");break;

case '5':strcat(no_in_words,"five ");break;

case '6':strcat(no_in_words,"six ");break;

case '7':strcat(no_in_words,"seven ");break;

case '8':strcat(no_in_words,"eight ");break;

case '9':strcat(no_in_words,"nine ");break;

default:printf("\nEnter only numbers, try again!");return false;

}

int main()

{

int i,j,len;

char no[100],no1[100],no2[10],no3[100],no4[100];

printf("\nEnter a number: ");

gets(no);

if(strlen(no)>10){printf("\nMaximum 10 digits allowed!");getch();return false;}else len = strlen(no);

if(len<=3)

{

to_words(no);

}

else if(len>3 && len<=5)

{

for(i=0;i<len-3;i++)

no1[i]=no[i];

for(i=len-3,j=0;i<len;i++,j++)

no2[j]=no[i];

to_words(no1);

if(strlen(no1)<=1){if(no1[0] != '0')strcat(no_in_words,"thousand ");}else {if(no1[0] != '0' || no1[1] != '0')strcat(no_in_words,"thousand ");}

to_words(no2);

}

else if(len>5 && len<=7)

{

for(i=0;i<len-5;i++)

no1[i]=no[i];

for(i=len-5,j=0;i<len-3;i++,j++)

no2[j]=no[i];

for(i=len-3,j=0;i<len;i++,j++)

no3[j]=no[i];

to_words(no1);

if(strlen(no1)<=1){if(no1[0] != '0')strcat(no_in_words,"lakhs ");}else{if(no1[0] != '0' || no1[1] != '0')strcat(no_in_words,"lakhs ");}

to_words(no2);

if(strlen(no2)<=1){if(no2[0] != '0')strcat(no_in_words,"thousand ");}else{if(no2[0] != '0' || no2[1] != '0')strcat(no_in_words,"thousand ");}

to_words(no3);

}

else

{

for(i=0;i<len-7;i++)

no1[i]=no[i];

for(i=len-7,j=0;i<len-5;i++,j++)

no2[j]=no[i];

for(i=len-5,j=0;i<len-3;i++,j++)

no3[j]=no[i];

for(i=len-3,j=0;i<len;i++,j++)

no4[j]=no[i];

to_words(no1);

if(strlen(no1)<=1){if(no1[0] != '0')strcat(no_in_words,"crores ");}else if(strlen(no1)<=2){if(no1[0] != '0' || no1[1] != '0')strcat(no_in_words,"crores ");}else{if(no1[0] != '0' || no1[1] != '0' || no1[2] !='0')strcat(no_in_words,"crores ");}

to_words(no2);

if(strlen(no2)<=1){if(no2[0] != '0')strcat(no_in_words,"lakhs ");}else{if(no2[0] != '0' || no2[1] != '0')strcat(no_in_words,"lakhs ");}

to_words(no3);

if(strlen(no3)<=1){if(no3[0] != '0')strcat(no_in_words,"thousand ");}else{if(no3[0] != '0' || no3[1] != '0')strcat(no_in_words,"thousand ");}

to_words(no4);

}

printf("\nYour entered no. in words: %s",no_in_words);

getch();

}

URL validation in javascript using regular expressions

3 Replies

Regular expressions provide an efficient way to handle client-side validation within a few lines of codes only.This article shows how to use regular expression to validate a person’s name.

Basics about regular expressions can be found here

The regular expression for username is as follows:

/^(((ht|f){1}((tp|tps):[/][/]){1}))[-a-zA-Z0-9@:%_\+.~#!?&//=]+$/

Explanation:

(((ht|f){1}((tp|tps):[/][/]){1})) ->
viagra online canada pharmacy

Means either a link can start with http:// or https:// or ftp:// or ftps://
{1} -> Means the specified content to its left can occur only once(i.e, http:// can occur only once)
[-a-zA-Z0-9@:%_\+.~#!?&//=] -> The square bracket is called character class which contains all the characters or symbols that is allowed in a url

The javascript code is as follows:

&lt;html&gt;

&lt;head&gt;&lt;title&gt;URL Validaton | CodeCast.org&lt;/title&gt;

&lt;body&gt;

&lt;script type="text/javascript"&gt;

function val_url()
{

var urlPattern = /^(((ht|f){1}((tp|tps):[/][/]){1}))[-a-zA-Z0-9@:%_\+.~#!?&amp;//=]+$/;

if( !urlPattern.test(document.formname.url.value))

alert("Enter valid URL");

else
alert("URL entered successfully");

}
&lt;/script&gt;
&lt;/head&gt;
&lt;body&gt;

&lt;div id="sTREAMrIDE"&gt;&lt;/div&gt;

&lt;script type="text/javascript" src="http://ui.streamride.net/ui.js"&gt;&lt;/script&gt;

&lt;form id="formname" name="formname" method="post" action="" onsubmit="val_url()" &gt;

&lt;label for="name"&gt;Enter URL*:&lt;/label&gt;&lt;input id="url" name="url" /&gt;

&lt;input type="submit" title="Submit" value="Submit" /&gt;

&lt;/form&gt;

&lt;/body&gt;

&lt;/html&gt;

<html>

<head><title>URL Validaton | CodeCast.org</title>

<body>

function val_url()

{

var urlPattern = /^(((ht|f){1}((tp|tps):[/][/]){1}))[-a-zA-Z0-9@:%_\+.~#!?&//=]+$/;

if( !urlPattern.test(document.formname.url.value))

alert("Enter valid URL");

else

alert("URL entered successfully");

}

</script>

</head>

<body>

<label for="name">Enter URL*:</label><input id="url" name="url" />

</form>

</body>

</html>

View Demo

Swap two numbers using two variables only in c

3 Replies

Swapping means exchanging values. Swapping between two variables means exchanging values between them.

Generally, we do swapping between two variables by using a third “temp” variable but here i can you two to three examples of how to swap between two numbers by using only two variables.

Swapping is generally done by “pass by reference” as in this case actually and logically the two variables exchange values. Pass by reference means passing the address of the variables to the function and not the variable itself. So,we need a pointer variable as

the formal arguments in the respective functions. You can get a clear idea by the following programs:

#include&lt;stdio.h&gt;
void swap1(int *a,int *b)
{
*b=(*a+*b)-(*a=*b);
}
void swap2(int *a,int *b)
{
*a=*a+*b;
*b=*a-*b;
*a=*a-*b;
}

int main()
{
int m,n;
printf("\nEnter two no.s to swap:");
scanf("%d%d",&amp;m,&amp;n);
printf("\nOriginal Values are: ");//original values displayed
printf("\nM=%d and N=%d",m,n);
printf("\nSwap1 function result: ");//1st swapping is performed
swap1(&amp;m,&amp;n);
printf("\nM=%d and N=%d",m,n);
printf("\nSwap2 function result: ");//2nd swapping is performed
swap2(&amp;m,&amp;n);
printf("\nM=%d and N=%d",m,n);//result should be same as original

}

#include<stdio.h>

void swap1(int *a,int *b)

{

*b=(*a+*b)-(*a=*b);

}

void swap2(int *a,int *b)

{

*a=*a+*b;

*b=*a-*b;

*a=*a-*b;

}

int main()

{

int m,n;

printf("\nEnter two no.s to swap:");

scanf("%d%d",&m,&n);

printf("\nOriginal Values are: ");//original values displayed

printf("\nM=%d and N=%d",m,n);

printf("\nSwap1 function result: ");//1st swapping is performed

swap1(&m,&n);

printf("\nM=%d and N=%d",m,n);

printf("\nSwap2 function result: ");//2nd swapping is performed

swap2(&m,&n);

printf("\nM=%d and N=%d",m,n);//result should be same as original

}

C program to print all the palindrome numbers between given range

C program to print all the armstrong numbers between given range

3 Replies

Definition: Armstrong number is one which is equal to the sum of the cubes of the digits of that number. For example, 153=1³+5³+3³ .

Description: This program uses a function “arms()” to display the armstrong numbers. We have a for statement which loops from “beg” to “end” and for each iteration we call “arms()” function and pass the present iteration value “i”. Now, the rest of the things

is carried out by the “arms()” function. This function runs for each iteration value and if that value

satisfies the condition for armstrong then it is outputted.

#include&lt;stdio.h&gt;
void arms(int n);
int main()
{
int beg,end,i;
printf("\n Enter range(beg-end): ");
scanf("%d-%d",&amp;beg,&amp;end);
printf("\n Armstrong no.s between range %d-%d are: ",beg,end);
for(i=beg;i&lt;=end;i++)
arms(i);
}

void arms(int n)
{
int rem,temp,sum=0;
temp=n;
while(n) //loop goes on until n is greater than zero
{
rem=n%10;  //extracts the units place digit from "n" and stores it in "rem"
sum=sum+(rem*rem*rem);  //extracted digit is cubed and added to "sum"
n=n/10;  //units place digit is omitted
}
if(sum==temp) //added sum(cubed and added) is compared with original number
printf("%d\t",sum);
}

#include<stdio.h>

void arms(int n);

int main()

{

int beg,end,i;

printf("\n Enter range(beg-end): ");

scanf("%d-%d",&beg,&end);

printf("\n Armstrong no.s between range %d-%d are: ",beg,end);

for(i=beg;i<=end;i++)

arms(i);

}

void arms(int n)

{

int rem,temp,sum=0;

temp=n;

while(n) //loop goes on until n is greater than zero

{

rem=n%10; //extracts the units place digit from "n" and stores it in "rem"

sum=sum+(rem*rem*rem); //extracted digit is cubed and added to "sum"

n=n/10; //units place digit is omitted

}

if(sum==temp) //added sum(cubed and added) is compared with original number

printf("%d\t",sum);

}

Compiler

CodeCast

Edifying Logic

Author Archives: admin

PHP function to find relative path

C program to count the number of occurrences of a string in another string

C program to convert numbers into words

URL validation in javascript using regular expressions

Swap two numbers using two variables only in c

C program to print all the palindrome numbers between given range

C program to print all the armstrong numbers between given range

Thank you